从列表中创建一个__init__类(make a class __init__ from a list)

 我有这样的东西，硬编码： 
 
class csv_row:
  def __init__(self, name, time, more_stuff):
    self.name = name
    self.time = time
    self.more_stuff = more_stuff
 
 这个类是csv行的表示。 我想要做的是使它更通用，并抓住csv文件的头部并使用它以与此列表相同的方式初始化它。 像这样的东西： 
 
class csv_row:
  def __init__(self, list_of_attrs):
    for column in list_of_attrs:
      # initialize a self.variable with the same name as the column 
 
 例如，csv的标题是[name, time, something] 。 传递的__init__将初始化为： 
 
self.name = name
self.time = time
self.something = something
 
 如何才能做到这一点？ 

I have something like this, hardcoded:
 
class csv_row:
  def __init__(self, name, time, more_stuff):
    self.name = name
    self.time = time
    self.more_stuff = more_stuff
 
this class is the representation of a csv row. What I want to do is make this more generic, and grab the head of the csv file and use it to initialize it in the same way as this list. Something like so:
 
class csv_row:
  def __init__(self, list_of_attrs):
    for column in list_of_attrs:
      # initialize a self.variable with the same name as the column 
 
for example, the header for a csv is [name, time, something]. The __init__, when passed that, will initialize with:
 
self.name = name
self.time = time
self.something = something
 
How can this be done?

原文：https://stackoverflow.com/questions/23275587